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Possible Answers: steel.
Last seen on: The Washington Post Crossword – June 14 2017
Random information on the term “Hard metal”:
Cemented carbide is a hard material used extensively in cutting tools for machining, as well as other industrial applications. It consists of fine particles of carbide cemented into a composite by a binder metal. Cemented carbides commonly use tungsten carbide (WC), titanium carbide (TiC), or tantalum carbide (TaC) as the aggregate. Mentions of “carbide” or “tungsten carbide” in industrial contexts usually refer to these cemented composites.
Most of the time, carbide cutters will leave a better surface finish on the part, and allow faster machining than high-speed steel or other tool steels. Carbide tools can withstand higher temperatures at the cutter-workpiece interface than standard high-speed steel tools (which is a principal reason for the faster machining). Carbide is usually superior for the cutting of tough materials such as carbon steel or stainless steel, as well as in situations where other cutting tools would wear away faster, such as high-quantity production runs.
Random information on the term “steel”:
Ferrite is a body-centered cubic (BCC, alpha iron) form of iron. It is this crystalline structure which gives steel and cast iron their magnetic properties, and is the classic example of a ferromagnetic material.
It has a strength of 280 N/mm2[citation needed] and a hardness of approximately 80 Brinell.
Below 910 °C (1,670 °F) the body-center-cubic allotrope of pure iron is stable. Above this temperature the face-centred cubic allotrope of iron, austenite (gamma-iron) is stable. Above 1,390 °C (2,530 °F), up to the melting point at 1,539 °C (2,802 °F), the body-centred cubic crystal structure is again the more stable form, as delta-ferrite (δ-Fe). Ferrite above the critical temperature A2 (Curie temperature) of 771 °C (1,044 K; 1,420 °F), where it is paramagnetic rather than ferromagnetic. The term is beta ferrite or beta iron (β-Fe). The term beta iron is not any longer used because it is crystallographically identical to, and its phase field contiguous with, α-Iron.